y^2-1/4y+7/4=0

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Solution for y^2-1/4y+7/4=0 equation: 



y^2-1/4y+7/4=0



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R



We calculate fractions


y^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{2}=0$

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